分步 a推导 0<x<y<10 < x < y < 10<x<y<1 时的联合密度 fX(i),X(j)(x,y)f_{X_{(i)},X_{(j)}}(x,y)fX(i),X(j)(x,y)。提交作答后加载提示与解析。
分步 b利用 i<ji < ji<j 时 E[X(i)X(j)]=i(j+1)(n+1)(n+2)E[X_{(i)}X_{(j)}] = \frac{i(j+1)}{(n+1)(n+2)}E[X(i)X(j)]=(n+1)(n+2)i(j+1),推导 Cov(X(i),X(j))\operatorname{Cov}(X_{(i)}, X_{(j)})Cov(X(i),X(j))。提交作答后加载提示与解析。