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1964Negative Exponential Tilt 19Minimize J(x)=16 e x + 4 e -2x . What x minimizes J?数学困难derivation未尝试免费1965Derive the Optimizer for a Linear-Softplus Objective 20For 0<m<n, derive the unique maximizer of K(x)=m x - n ln(1+e x).数学困难derivation未尝试免费1966Balanced Softplus Tradeoff 21The linear reward and saturation penalty balance exactly at a central point. The desk maximizes K(x) = 2 x - 4 ln(1+e x). What x is optimal?数学简单数值题未尝试免费1967Positive Softplus Tilt 22The linear reward is strong relative to the saturation penalty, so the optimum should be positive. The desk maximizes K(x) = 3 x - 4 ln(1+e x). What x is optimal?数学简单derivation未尝试免费1968Negative Softplus Tilt 23The saturation penalty dominates until x turns sufficiently negative. The desk maximizes K(x) = 1 x - 3 ln(1+e x). What x is optimal?数学中等derivation未尝试免费1969Which Side of Zero Is Optimal in the Linear-Softplus Problem 24For K(x)=m x - n ln(1+e x) with 0<m<n/2, is the unique optimizer positive, zero, or negative?数学中等derivation未尝试免费1970Maximum Value at the Interior Utility-Impact Optimum 25For F(x)=4 ln(1+x)-x 2 on x>-1, what x maximizes F and what is the maximum value?数学困难derivation未尝试免费1971Cheapest Two-Book Hedge 1Two hedge books carry different quadratic slippage penalties but must deliver one joint exposure target. Minimize L(x,y) = 1x 2 + 4y 2 subject to 1x + 2y = 10.数学简单数值题未尝试免费1972Derive the Two-Book Hedge Formula 2Derive the minimizer of a x 2 + b y 2 subject to u x + v y = c for positive a,b.数学简单derivation未尝试免费1973How the Cheap Book Gets More Size 3In the problem min a x 2 + b y 2 subject to x+y=c, which book gets the larger allocation when a<b, and why?数学中等derivation未尝试免费1974Weighted Exposure Hedge Split 4The first hedge line loads twice as much on the required exposure as the second, but also has its own quadratic penalty. Minimize L(x,y) = 2x 2 + 3y 2 subject to 2x + 1y = 12.数学中等数值题未尝试免费1975Three-to-One Loading Tradeoff 5One book moves the target much faster per unit notional, so the optimizer must trade off load efficiency and cost. Minimize L(x,y) = 3x 2 + 1y 2 subject to 1x + 3y = 9.数学困难derivation未尝试面试订阅1976Three-Book Budget Allocation 6Three sleeves have different quadratic slippage penalties but must add up to a fixed total size. Minimize Q(x,y,z) = 1x 2 + 2y 2 + 4z 2 subject to x+y+z = 28.数学简单数值题未尝试免费1977Derive the Three-Book Total-Size Allocation 7Derive the minimizer of a x 2 + b y 2 + c z 2 subject to x+y+z=N for positive a,b,c.数学中等derivation未尝试免费1978Why the Three-Book Solution Is Inverse-Coefficient Weighted 8In min a x 2 + b y 2 + c z 2 subject to x+y+z=N, why do larger quadratic coefficients receive smaller allocations?数学中等derivation未尝试免费1979Minimum Objective Value Under a Total-Size Constraint 9For positive a,b,c, what is the minimum value of a x 2 + b y 2 + c z 2 subject to x+y+z=N?数学中等derivation未尝试免费1980Minimum Risk Needed for a Target Alpha 10A desk wants to minimize a x 2 + b y 2 subject to mu 1 x + mu 2 y = A. What is the minimum achievable value?数学困难derivation未尝试面试订阅1981Three-Book Split With a Fixed Spread 11The first and third books must keep a pre-agreed spread while total size stays fixed. Minimize 1x 2 + 1y 2 + 1z 2 subject to x+y+z=9 and x-z=1.数学简单数值题未尝试免费1982Asymmetric Spread-Constrained Allocation 12The left book is more expensive per unit, so the optimizer cannot simply split the spread evenly. Minimize 2x 2 + 1y 2 + 1z 2 subject to x+y+z=10 and x-z=2.数学简单数值题未尝试免费1983Derive the Total-and-Spread Solution 13For positive a,b,c, derive the minimizer of a x 2 + b y 2 + c z 2 subject to x+y+z=N and x-z=d.数学中等derivation未尝试免费